Wednesday, 11 November 2009

SECOND SESSIONAL TEST (odd SEMESTER 2009-10) B.Tech…first Semester Sub Name: Engineering Mechanics


SECOND SESSIONAL TEST (odd SEMESTER 2009-10)
B.Tech…first Semester

Sub Name: Engineering Mechanics                                         Max. Marks: 30
Sub Code: EME-201                                                          Max. Time: 2: 00 Hr

Group A

Q.1 Choose the correct answer of the following questions 1x6=6

(i) If two forces of equal magnitudes have a resultant force of the same magnitude then the angle between them is
(a) 00          (b) 900         (c) 1200          (d) 1350
Ans: ( c)

Explanation: P2 = P2 + P2 +2P.P.cos θ
ð      P²= P² (1+2cos θ)
ð      cos θ = -½
ð      θ = 120°

(ii) If a ladder is kept at rest on a vertical wall making an angle θ with horizontal. If co-efficient of the friction in all the surfaces be µ, then the tangent of the angle θ will be equal to
(a) (1-µ2)/2µ                                  (b) (1-µ)2 /2µ
(c) (1-µ)/2µ                                   (d) none of the above

Explanation: (a) (1-µ2)/2µ

(iv) Varignon’s theorem is related with _____________ .
Answer: moment

(v) If two forces of equal magnitudes P having an angle (90°- θ) between them, then their resultant force will be equal to ________.
Answer: √2P (1+sin θ)

(vi) A fixed joint produces
(a) 1             (b) 2             (c) 3               (d) 4         reactions
Answer: (c ) 3

(vii) The equilibrium conditions of concurrent force system is_________.
Answer: ∑Fx =0; ∑Fy=0.


Group B                                                                                                                  8x3=24

Attempt any three questions
Q.2. State and explain Varignon’s theorem of moment. Three forces of magnitudes 3 KN, 4 KN and 2KN act along the three side of an equilateral triangle ∆ABC in order. Find the position, direction and magnitude of the resultant force.         4+4

Answer: resultant force: √3 KN

Q.3  (a) Two cylindrical rollers are kept at equilibrium inside a jar or channel as shown in the figure. The channel width is 1000 mm, where as the rollers have diameters 600 mm and 800 mm respectively. The weights are 2 kN and 5 kN respectively. Find all the reactions at contacts.
                                                                                            4+4

(b) What is pure bending? If a stone is thrown with a velocity 400 m/s then find the maximum height that the stone can reach.







Q:4)  a) Classify different types of joints in beam with proper explanations.

(b) Find the reactions at the support for the beam as shown in the figure.                                           4+4
















Monday, 9 November 2009


ENGINEERING. MECHANICS:  

Most Common Theoretical Questions

EME - 102; EME - 201


FORCE AND FORCE SYSTEM




Topic: FORCE SYSTEM

1) What is a FORCE SYSTEM? Classify them with examples and diagrams.

Ans: A force system may be defined as a system where more than one force act on the body. It means that whenever multiple forces act on a body, we term the forces as a force system. We can further classify force system into different sub-categories depending upon the nature of forces and the point of application of the forces.

Different types of force system:


(i) COPLANAR FORCES:

If two or more forces rest on a plane, then they are called coplanar forces. There are many ways in which forces can be manipulated. It is often easier to work with a large, complicated system of forces by reducing it an ever decreasing number of smaller problems. This is called the "resolution" of forces or force systems. This is one way to simplify what may otherwise seem to be an impossible system of forces acting on a body. Certain systems of forces are easier to resolve than others. Coplanar force systems have all the forces acting in in one plane. They may be concurrent, parallel, non-concurrent or non-parallel. All of these systems can be resolved by using graphic statics or algebra.


(ii) CONCURRENT FORCES:

A concurrent coplanar force system is a system of two or more forces whose lines of action ALL intersect at a common point. However, all of the individual vectors might not actually be in contact with the common point. These are the most simple force systems to resolve with any one of many graphical or algebraic options. If the line of actions of two or more forces passes through a certain point simultaneously then they are called concurrent forces. concurrent forces may or may not be coplanar.

(iii) LIKE FORCES:

A parallel coplanar force system consists of two or more forces whose lines of action are ALL parallel. This is commonly the situation when simple beams are analyzed under gravity loads. These can be solved graphically, but are combined most easily using algebraic methods. If the lines of action of two or more forces are parallel to each other, they are called parallel forces and if their directions are same, then they are called LIKE FORCES.

(iv) UNLIKE FORCES: If the parallel forces are such that their directions are opposite to each other, then they are termed as "UNLIKE FORCE".


(v) NON COPLANAR FORCES:
The last illustration is of a "non-concurrent and non-parallel system". This consists of a number of vectors that do not meet at a single point and none of them are parallel. These systems are essentially a jumble of forces and take considerable care to resolve.

_________________________________________________________________________________
N.B. Almost any system of known forces can be resolved into a single force called a resultant force or simply a Resultant. The resultant is a representative force which has the same effect on the body as the group of forces it replaces. (A couple is an exception to this) It, as one single force, can represent any number of forces and is very useful when resolving multiple groups of forces. One can progressively resolve pairs or small groups of forces into resultants. Then another resultant of the resultants can be found and so on until all of the forces have been combined into one force. This is one way to save time with the tedious "bookkeeping" involved with a large number of individual forces. Resultants can be determined both graphically and algebraically.The Parallelogram Method and the Triangle Method. It is important to note that for any given system of forces, there is only one resultant.


It is often convenient to decompose a single force into two distinct forces. These forces, when acting together, have the same external effect on a body as the original force. They are known as components. Finding the components of a force can be viewed as the converse of finding a resultant. There are an infinite number of components to any single force. And, the correct choice of the pair to represent a force depends upon the most convenient geometry. For simplicity, the most convenient is often the coordinate axis of a structure.


A force can be represented as a pair of components that correspond with the X and Y axis. These are known as the rectangular components of a force. Rectangular components can be thought of as the two sides of a right angle which are at ninety degrees to each other. The resultant of these components ...


is the hypotenuse of the triangle. The rectangular components for any force can be found with trigonometrical relationships: Fx = Fcosθ, Fy = Fsinθ. There are a few geometric relationships that seem to common in general building practice in North America. These relationships relate to roof pitches, stair pitches, and common slopes or relationships between truss members. Some of these are triangles with sides of ratios of 3-4-5, 1-2-sqrt3, 1-1-sqrt2, 5-12-13 or 8-15-17. Committing the first three to memory will simplify the determination of vector magnitudes when resolving more difficult problems.


When forces are being represented as vectors, it is important to should show a clear distinction between a resultant and its components. The resultant could be shown with color or as a dashed line and the components as solid lines, or vice versa. NEVER represent the resultant in the same graphic way as its components.


Any concurrent set of forces, not in equilibrium, can be put into a state of equilibrium by a single force. This force is called the Equilibrant. It is equal in magnitude, opposite in sense and co-linear with the resultant. When this force is added to the force system, the sum of all of the forces is equal to zero. A non-concurrent or a parallel force system can actually be in equilibrium with respect to all of the forces, but not be in equilibrium with respect to moments.
__________________________________________________________________________________


2) What is STATIC EQUILIBRIUM? 
    What are the conditions of static equilibrium for
            (i) concurrent force system
            (ii) coplanar non concurrent force system.

Ans: A body is said to be in equilibrium when there is no change in position as well as no rotation exist on the body. So to be in equilibrium process, there must not be any kind of motions ie there must not be any kind of translational motion as well as rotational motion.

We also know that to have a linear translational motion we need a net force acting on the object towards the direction of motion, again to induce an any kind of rotational motion, a net moment must exists acting on the body. Further it can be said that any kind of complex motion can be resolved into a translational motion coupled with a rotating motion.

Therefore a body subjected to a force system would be at rest if and only if the net force as well as the net moment on the body be zero. Therefore the general condition of any system to be in static equilibrium we have to satisfy two conditions

(i) Net force on the body must be zero ie, ΣFi = 0;
(ii) Net moment on the body must be zero ie, ΣMi = 0.

Now we can apply these general conditions to different types of Force System.

For concurrent force system total moment about the concurrent point is always zero as all the forces pass through the point, and we know the moment of a force passing through the point about which we shall take moment is always zero. Hence, the conditions of equilibrium for concurrent forces will be  
Net force on the body must be zero ie, ΣFi = 0; and we can resolve it along X axis and along Y axis, ie.  (i) ΣFx = 0; and  (ii) ΣFy = 0.

for coplanar non concurrent force system, the equilibrium conditions are
(i) ΣFx = 0; and  (ii) ΣFy = 0.  (iii)  ΣMi = 0.


 Moment on a plane:

For a force system the total resultant moment about any arbitrary point due to the individual forces are equal to the moment produced by the resultant about the same point. Now if the system is at equilibrium condition, then the resultant force would be zero. Hence, the moment produced by the resultant about any arbitrary point is zero. In case of coplanar & concurrent force system, as the forces are concurrent ie. each of the force passes through a common point. Hence, about that common point total moment of all the forces will be zero.

3) What are different types of joint? discuss them in details.

Answer: The Concepts of Joints. In Engineering terminology any force carrying linear member is called as links. Links can be attached to each other by the fasteners or joints. Hence, we can say to prevent the relative motion between two links completely or partially we use fasteners or joints.



Basically there are three types of joints which we shall discuss and they are named as,
(i) pin/ hinged joints, 
(ii) roller joints and 
(iii) fixed joints.


PIN JOINTS:

They are classified according to the degrees of freedom of the links they would allow. Like a pin or hinge joint is consisted of two links joined by the insertion of a pin at the pivot hole. A pin joint doesn't allow a vertical or horizontal relative velocities between the two links.

For better understanding of the mechanism of pin joint we would like to make a simplest type of pin joints. Suppose we would take two links and make holes at one of the ends of each link. Now if we insert a bolt through the holes of both the links, then what we get is an example of pin/hinge joints.

A pin joint although restricts any kind of horizontal or vertical displacement but they can not restrict rotation about an axis passing through the hole, in clockwise or anti clockwise direction. Hence it provides two reactions one vertical and one horizontal to restrict any kind of movement along that direction.

ROLLER JOINTS:


 

MULTIPLE CHOICE QUESTIONS:
sub: engg. mechanics.
Sub: Engineering Mechanics,
Sub Code: EME-202, Semester: 2nd Sem, Course: B.Tech

Q.1) The example of Statically indeterminate structures are,
a. continuous beam,
b. cantilever beam,
c. over-hanging beam,
d. both cantilever and fixed beam.

Q.2) A redundant truss is defined by the truss satisfying the equation,
a. m = 2j - 3,
b. m < 2j + 3, 
c. m > 2j - 3,
d. m > 2j + 3

Q.3) The property of a material to withstand a sudden impact or shock is called,
a. hardness 

b. ductility, 
c. toughness, 
d. elasticity of the material

Q.4) The stress generated by a dynamic loading is approximately _____ times of the stress developed by the gradually applying the same load.

Q.5) The ratio between the volumetric stress to the volumetric strain is called as
a. young's modulus
b. modulus of elasticity
c. rigidity modulus,
d. bulk modulus

Q.6) In a Cantilever beam, the maximum bending moment is induced at
a. at the free end
b. at the fixed end
c. at the mid span of the beam
d. none of the above

Q.7) The forces which meet at a point are called
a. collinear forces
b. concurrent forces
c. coplanar forces
d. parallel forces

Q.8) The coefficients of friction depends upon
a. nature of the surface
b. shape of the surface
c. area of the contact surface
d. weight of the body

Q.9) The variation of shear force due to a triangular load on simply supported beam is
a. uniform 
b. linear 
c. parabolic 
d. cubic

Q.10) A body is on the point of sliding down an inclined plane under its own weight. If the inclination of the plane is 30 degree, then the coefficient of friction between the planes will be

a. 1/√3
b. √3
c. 1
d. 0

11. A force F of 10 N is applied on a mass of 2 kg. What is the acceleration of the mass?
A. 2 m/s²
B. 5 m/s²
C. 10 m/s²
D. 20 m/s²
Answer: B

12. What is the moment of a force of 50 N applied at a distance of 2 meters from a fixed point?
A. 25 Nm
B. 50 Nm
C. 100 Nm
D. 200 Nm
Answer: C

13. A 2000 kg car traveling at 20 m/s collides with a 500 kg car traveling at 10 m/s in the opposite direction. What is the velocity of the cars after the collision?
A. 6.7 m/s
B. 10 m/s
C. 13.3 m/s
D. 16.7 m/s
Answer: A

14. A 500 N force is applied to a 100 kg object on a flat surface. What is the coefficient of static friction if the object is just about to move?
A. 0.5
B. 0.7
C. 0.8
D. 1.0
Answer: D

15. A beam of length 4 m and moment of inertia of 1000 kg/m² is supported at each end. What is the maximum load that the beam can support if it is uniformly loaded?
A. 500 N
B. 1000 N
C. 2000 N
D. 4000 N
Answer: C

16. A block of mass 2 kg is hanging from a string. What is the tension in the string if the block is stationary?
A. 19.6 N
B. 20 N
C. 29.4 N
D. 30 N
Answer: B

17. A roller coaster car of mass 500 kg is traveling at 20 m/s at the bottom of a  loop-the-loop. What is the minimum radius of the loop required for the car to remain in contact with the track?
A. 40 m
B. 50 m
C. 60 m
D. 70 m
Answer: D

18. A body of mass 10 kg is moving with a velocity of 5 m/s. What is the kinetic energy of the body?
A. 50 J
B. 100 J
C. 125 J
D. 250 J
Answer: B

19. A body of mass 5 kg is placed on an inclined plane which makes an angle of 30° with the horizontal. What is the force acting on the body parallel to the plane?
A. 4.9 N
B. 7.5 N
C. 8.7 N
D. 10 N
Answer: B

20. A force of 100 N is applied on a body of mass 20 kg. What is the work done by the force in moving the body through a distance of 5 meters?
A. 250 J
B. 500 J
C. 1000 J
D. 2000 J
Answer: B

21. What is the principle of moments?
A. The sum of the moments about any point of a system in equilibrium is zero.
B. The sum of the forces acting on a system in equilibrium is zero.
C. The sum of the torques acting on a system in equilibrium is zero.
D. The sum of the accelerations of a system in equilibrium is zero.

Answer: A

22. What is the difference between static and dynamic equilibrium?
A. In static equilibrium, there is no motion, while in dynamic equilibrium, there is motion.
B. In static equilibrium, the forces are balanced, while in dynamic equilibrium, the forces are unbalanced.
C. In static equilibrium, the sum of the forces and moments is zero, while in dynamic equilibrium, the sum of the forces and moments is not zero.
D. In static equilibrium, the sum of the forces and moments is not zero, while in dynamic equilibrium, the sum of the forces and moments is zero.

Answer: C

23. What is the moment of inertia?
A. The resistance of an object to angular acceleration.
B. The force required to rotate an object.
C. The distance between the center of mass and the axis of rotation.
D. The angular velocity of an object.

Answer: A

24.What is the difference between stress and strain?
A. Stress is the deformation per unit length, while strain is the force per unit area.
B. Stress is the force per unit area, while strain is the deformation per unit length.
C. Stress is the force applied to an object, while strain is the resulting deformation.
D. Stress is the resistance of an object to deformation, while strain is the resistance of an object to stress.

Answer: B

25. What is Hooke's Law?
A. The stress applied to an elastic material is proportional to the strain produced.
B. The strain produced in an elastic material is proportional to the stress applied.
C. The deformation produced in an elastic material is proportional to the force applied.
D. The force applied to an elastic material is proportional to the deformation produced.

Answer: A

26.What is the difference between a beam and a truss?
A. A beam is a one-dimensional structure, while a truss is a two-dimensional structure.
B. A beam is made up of several members connected at their ends, while a truss is made up of several members connected at their joints.
C. A beam is used to support loads that are perpendicular to its axis, while a truss is used to support loads that are parallel to its axis.
D. A beam is a rigid structure, while a truss is a flexible structure.

Answer: B

27. What is the difference between a force and a moment?
A. A force is a vector quantity, while a moment is a scalar quantity.
B. A force is a scalar quantity, while a moment is a vector quantity.
C. A force is a push or a pull, while a moment is a twist or a turn.
D. A force is a linear motion, while a moment is a rotational motion.

Answer: C

28. What is the center of mass?
A. The point where the weight of an object is concentrated.
B. The point where the forces acting on an object are balanced.
C. The point where the moments acting on an object are balanced.
D. The point where the acceleration of an object is zero.

Answer: A

29. What is the method used to determine the forces in a truss?
A. Method of joints
B. Method of sections
C. Both A and B
D. None of the above

Answer: C

30. In a truss, which members are in tension and which members are in compression?
A. All members are in tension.
B. All members are in compression.
C. Members with angled force vectors are in tension, and members with vertical force vectors are in compression.
D. Members with vertical force vectors are in tension, and members with angled force vectors are in compression.

Answer: C

31. What is the difference between a simple truss and a compound truss?
A. A simple truss is made up of one triangle, while a compound truss is made up of two or more triangles.
B. A simple truss is made up of straight members only, while a compound truss may have curved members.
C. A simple truss is statically determinate, while a compound truss may be statically indeterminate.
D. A simple truss is used for short spans, while a compound truss is used for long spans.

Answer: A

32.How many unknown forces are there in a simple truss?
A. 2
B. 3
C. 4
D. It depends on the number of joints in the truss.

Answer: B

33. What is the method used to analyze a truss with multiple loadings?
A. Superposition method
B. Substitution method
C. Iterative method
D. None of the above

Answer: A

34. What is the maximum number of reactions that can be present in a truss?
A. 1
B. 2
C. 3
D. 4

Answer: B

35. What is the difference between a statically determinate and a statically indeterminate truss?
A. A statically determinate truss has only one solution for the unknown forces, while a statically indeterminate truss may have more than one solution.
B. A statically determinate truss has more unknown forces than the number of equations available to solve them, while a statically indeterminate truss has fewer unknown forces than the number of equations available to solve them.
C. A statically determinate truss is easier to analyze, while a statically indeterminate truss requires more advanced techniques.
D. A statically determinate truss is always more efficient than a statically indeterminate truss.

Answer: C

36. What is the difference between a pinned support and a roller support?
A. A pinned support allows rotation but not translation, while a roller support allows translation but not rotation.
B. A pinned support allows both rotation and translation, while a roller support allows neither.
C. A pinned support is used for horizontal loads, while a roller support is used for vertical loads.
D. A pinned support is always more stable than a roller support.

Answer: A

37. What is the maximum number of members that can be present in a simple truss?
A. 2n-2, where n is the number of joints
B. 2n-3, where n is the number of joints
C. n-1, where n is the number of joints
D. n+1, where n is the number of joints

Answer: B

©subhankar_karmakar

more OBJECTIVE QUESTIONS on ENGINEERING MECHANICS 

ASSIGNMENT ON THERMODYNAMICS



Numericals on Thermodynamics:

1.     Mass enters an open system with one inlet and one exit at a constant rate of 50 kg/min. At the exit, the mass flow rate is 60 kg/min. If the system initially contains 1000 kg of working fluid, determine the time when the system mass becomes 500 kg.

2.     Mass leaves an open system with a mass flow rate of c*m, where c is a constant and m is the system mass. If the mass of the system at t = 0 is m0, derive an expression for the mass of the system at time t.

3.     Water enters a vertical cylindrical tank of cross-sectional area 0.01 m2 at a constant mass flow rate of 5 kg/s. It leaves the tank through an exit near the base with a mass flow rate given by the formula 0.2h kg/s, where h is the instantaneous height in m. If the tank is empty initially, develop an expression for the liquid height h as a function of time t. Assume density of water to remain constant at 1000 kg/m3.

4.     A conical tank of base diameter D and height H is suspended in an inverted position to hold water. A leak at the apex of the cone causes water to leave with a mass flow rate of c*sqrt(h), where c is a constant and h is the height of the water level from the leak at the bottom. (a) Determine the rate of change of height h. (b) Express h as a function of time t and other known constants, rho (constant density of water), D, H, and c if the tank was completely full at t=0.

5.     Steam enters a mixing chamber at 100 kPa, 20 m/s, with a specific volume of 0.4 m3/kg. Liquid water at 100 kPa and 25oC enters the chamber through a separate duct with a flow rate of 50 kg/s and a velocity of 5 m/s. If liquid water leaves the chamber at 100 kPa and 43oC with a volumetric flow rate of 3.357 m3/min and a velocity of 5.58 m/s, determine the port areas at the inlets and exit. Assume liquid water density to be 1000 kg/m3 and steady state operation.

6.     Air is pumped into and withdrawn from a 10 m3 rigid tank as shown in the accompanying figure. The inlet and exit conditions are as follows. Inlet: v1= 2 m3/kg, V1= 10 m/s, A1= 0.01 m2; Exit: v2= 5 m3/kg, V2= 5m/s, A2= 0.015 m2. Assuming the tank to be uniform at all time with the specific volume and pressure related through p*v=9.0 (kPa.m3), determine the rate of change of pressure in the tank.

7.     A gas flows steadily through a circular duct of varying cross-section area with a mass flow rate of 10 kg/s. The inlet and exit conditions are as follows. Inlet: V1= 400 m/s, A1= 179.36 cm2; Exit: V2= 584 m/s, v2= 1.1827 m/kg. (a) Determine the exit area. (b) Do you find the increase in velocity of the gas accompanied by an increase in flow area counter intuitive? Why?


8.     Steam enters a turbine with a mass flow rate of 10 kg/s at 10 MPa, 600oC, 30 m/s, it exits the turbine at 45 kPa, 30 m/s with a quality of 0.9. Assuming steady-state operation, determine (a) the inlet area, and (b) the exit area. 
Answers: (a) 0.01279 m2 (b) 1.075 m2

Friday, 18 September 2009

CONCEPTS OF THERMODYNAMICS AND ITS LAWS

When I joined IEC College of Engg & Technology in 1999, for the first time I heard of Richard Feynman & his style of writings. His three volume Lectures on Physics changed me permanently. The language was lucid and he told about the facts of Physics just like a thriller novel. I became a diehard fan of Physics and Feynman.
These piece of article on thermodynamic concept is an earnest try to tell about energy mechanics as a story.


"Dedicated to the teaching methodology of Richard Feynman"

. . . . . . . . . . . .©sarpyl

CONCEPTUAL IDEAS :

                                  If we want to analyze movement of energy over space, then we must define the space that would be used for the observation, we would call it as a SYSTEM, separated from the adjoining space that is known as "Surroundings", by a boundary that may be real or may be virtual depending upon the nature of the observation. The boundary is called as SYSTEM BOUNDARY.

                                  So we get a space of certain volume where ENERGY TRANSFER (movement of energy) is going on, what may or may not be real, and distinct, it may be virtual (in case of flow system ), again if real boundary exists, then it may be fixed (rigid boundary like constant volume system) or may be flexible (like cylinder-piston assembly). For a certain experiment the system and surroundings together is called UNIVERSE.

                                  The interface between the system & surroundings is called as "SYSTEM BOUNDARIES", which may be real & distinct in some cases where as some of them are virtual, but it may be real, solid and distinct.


ENERGY:

                                  Although we can't exactly define what is Energy, yet we can say how does Energy behave, even we can measure the change in energy of the system, we may say that Energy always posses the capability to do certain amount of work depending upon the form of Energy. We can also describe the different forms of Energy those can exist like potential energy, kinetic energy, chemical energy, binding energy, nuclear energy etc.

                                  Depending upon the capacity to do work, energy can be classified into different forms. If the energy is highly ordered then it is HIGH GRADE ENERGY, like Kinetic Energy, where as when Energy exists in a chaotic form we call it LOW GRADE ENERGY. Heat energy of a body arises due to random motions of the individual molecules. Hence we can say that HEAT ENERGY is related with the chaosness of the molecules, therefore, it is the most low grade energy.


HEAT TRANSFER :

                                  Through the boundary, a system and its surroundings can exchange energy between them, if allowed by the boundary properties. There are three modes of energy interaction a system and surroundings. If the boundaries are permeable to allow heat flow across it, then the energy transfer mode is called HEAT TRANSFER.

                                  When a system absorbs heat energy from the surroundings due to the temperature difference between system and surroundings the transfer of energy is named as HEAT TRANSFER.


WORK TRANSFER :

                                  When a system has a flexible or movable boundary then energy can be transfer by virtue of workdone. If there exists a pressure gradient between a system and its surroundings then work exchange takes place between the system and the surroundings as the flexible boundary moves to destroy the pressure gradient that exists between the system and the surroundings. So we would say the Energy Transfer due to pressure gradient is named as WORK TRANSFER.


MASS TRANSFER :

                                  For flow process in a open system, mass transfer takes place between system & surroundings which is the third type of Energy Transfer and named as Mass Transfer. Any open system has two passages for fluid flow. Through one passage, the mass of the working substance enters into the system and aptly named as INLET, while the second passage is used by the working fluid to flow out of the system and it is named as OUTLET. So, in open system mass flow occurs across the system and this phenomenon of mass inflow and outflow from the system is named as MASS TRANSFER between a system and it's boundaries.


CONCEPTS OF MASS :

                                  What is mass? Or we can say what is it to be a substance? Here, again we face the fundamental difficulty to define Mass accurately, although we know how it does behave, we can measure its value even, but it is really not clear what is mass made of. When Einstein equates mass in terms of energy, it defines mass as a form of energy but they are bound within the mass which again consists of elementary but composite particles named electron, proton & neutron. Proton, neutrons are made of QUARKS, which are the most fundamental particles of nature. Although Quarks are already well researched, and we know the most possible reason of the “confinement” phenomenon, still there exists a large number of physical phenomenon which can be explained using the “standard model of particle physics”.


PROPERTIES OF A SYSTEM :

                                  A system is characterized by the values of its properties. So the most logical question that would arise here would be about properties of a system. So what is a property of a system? It has been seen that every object that exists in this Universe possesses some physical & chemical characteristics, like size, shape, mass, energy, chemical composition, colors etc. Among these various characteristics, those are related with energy directly or indirectly are called as "thermodynamic functions". There are mainly two types of thermodynamic functions, which can be better described in mathematical terms as they are physical quantity and hence are measurable. Here we shall take a little hiatus (break) to know some facts about physical quantity.


                                   Physical characteristics are of two types. Any physical characteristics can be represented by the mathematical quantity and it is thus represented by mathematical functions. There may be two types of mathematical functions. When expressed in differential form, some of the functions become Exact differential and some of them produces In-exact differential form. The exact differential functions are called as thermodynamic properties. They are also known as “Point Functions”. Where as the in-exact differentials are called “Path Functions”


EQUILIBRIUM CONDITIONS :

                                   Every thermodynamic function are directly or indirectly measurable and when there is no energy transfer between the system and surroundings, then the value of the functions assume a certain value by which we can specify the state or condition of a thermodynamic system. So, the values are only measurable when they are not changing over a period of time. What does it implicate that the values of the thermodynamic functions are not continuously changing. When the values are not changing it indicates a stability of the state of the system over a certain periods of time. This stability of a system implies an Equilibrium condition. Each and every equilibrium states are distinct and they are specified by the distinct value of the properties of the system at that equilibrium conditions.


CONCEPTS OF A THERMODYNAMIC PLANE :

                                  A thermodynamics system is a bi-variate function. It means that to specify a thermodynamic system we need to specify the values of any two properties. One can also describe a thermodynamic system has two degrees of freedom. So, mathematically, we can say that any thermodynamic system at a certain equilibrium condition can be represented as a point on a two dimensional plane. The plane thus formed plotting thermodynamic properties along X and Y axes of a Cartesian Coordinate system is known as thermodynamic plane.

                                 A point on this plane represents a system at a thermodynamic equilibrium condition, which can be defined as a state which is time invariant when it is isolated from the surroundings. So, at equilibrium condition the values of different thermodynamic properties remain constant over a considerable amount of time.


EXTERNAL DISTURBANCES AND CHANGE OF STATE OF A SYSTEM:

                                 We have already know that when the values of different thermodynamic properties become stable we get an equilibrium state where no values of the properties can be changed without application of any external influences. But, what happens, when an external agency tries to change the values of the properties of the system. Here, what does it mean by "external influences"? What does it mean in real life? We know from our daily life experiences that any kind of external influences can be at last reduced to any kind of force only and the use of external influences always lead to an exchange of energy between the system and the surroundings. To explain the phenomena we shall take a system at equilibrium with its surroundings. Hence, the pressure P and temperature T of both the system as well as the surroundings too. Now, to disturb the equilibrium condition of the system we must change either the pressure or the temperature of the system. Suppose we take a cylinder-piston assembly, whose temperature is T and pressure is P. Now suppose, we inject a small amount of energy very slowly into the system, can you tell, what type of change we should expect in this case.

                                   Suppose we change the pressure from (P) to (P + dP) where (dP) is the change of pressure of the system, where as the pressure of the surroundings remains at (P). Then there exists a pressure difference of the flexible wall that separates our system from its surroundings. As a result a force will act on the flexible wall of the system, and the wall will move along the net force on it. Therefore, an amount of work done will be there due to the displacement of the boundary wall. There may be two type of cases, when (dP) is positive, the system does work on the surrounding as the volume of the system increases. As the volume increases from V to (V + dV) the pressure would drop to (P) from (P + dP). Hence due to this energy transfer from the system to surrounding again Equilibrium will be achieved.


VARIABLES IN THERMODYNAMICS

STATE AND COMPOSITION OF MATTER :

                                    From our common sense we can say that matters are composed of mass, a fundamental form of energy. From our early experimentation with mass and nature, we could conclude a concept of mass as a continuous physical quantity, it implies that we can divide any quantity of mass, whatever small it may be. This view is essentially evolved on the basis of our macro world perception.

                                    But within few years rapid growth of modern science shows that our perception of a continuous character of mass is an incorrect idea. Hence particle character was bestowed on mass that tells us that masses are made of tiny particles, that can independently exist in a stable condition and nicely named as molecules which are different for different materials. But it is not the fundamental particles of mass. There are more to come!

                                    So, a piece of matter is really made of very large numbers of stable molecules, which scientists conclude is made of atoms. Again atoms are composed of very tiny fundamental negatively charged particles named electrons, and the core of the atoms are called as nucleus is made of chargeless neutrons and positively charged protons.

                                    So mass is a discontinuous physical quantity and microscopic by nature! But our common perception says that it is a continuum and hence macroscopic by nature. Accordingly, there are two ways to learn thermodynamics, one is macroscopic approach, also known as Classical

                                    Thermodynamics. and the other was named as Statistical Thermodynamics. It is basically Energy Dynamics at microscopic level.


 ENERGY

                                    The focus of Thermodynamics: As the name suggests, is primarily on energy, more specifically heat energy and related variable.(Thermos means Heat energy and Temperature).

                                     So, first thermodynamic property is Energy itself! We use the term so frequently that we never think about its proper definition and understanding. Let me ask you one thing when someone mentions that he or she is feeling more energetic, what does he actually want to mean? In simple terms we can specify Energy as "something" that has the capacity to do work. Therefore, we can say that Energy has the capacity to do work, whatever it may be the change of anything is some way or other is connected with the exchange of Energy between bodies.


STORED ENERGY AND ENERGY IN TRANSITION :

                                     We have defined thermodynamics as the knowledge of Energy and its movement in the space, including the dynamics of the involved mechanisms and processes. So, our prime interest would be Energy here, hence Energy must be defined as a physical quantity (hence can be measured), which has the capacity to perform useful work against any resistance.

Here, the definition of work must be given, as thermodynamic work is different from mechanical work.


MECHANICAL WORK Vs. THERMODYNAMIC WORK:

                                     Classical or Newtonian Mechanics defines Work done as in a purely mechanical way. (a mechanical way means a macrobody having displacements). Whenever a body having a mass undergoes a displacement under the influence of a force on it, classical mechanics says a work done is there.

                                     So if F is a force vector acting on a particle due to which the particle moves travelling a "displacement" d which is also a vector, then the total work done by the force on the particle would be "dot product" of the vectors "F" and "d". So, mathematically Workdone, W can be expressed as W=F.d and in terms of "scalar" magnitude and
W=Fd CosΦ where Φ= Angle between F and d.


THERMODYNAMIC WORK:

                                     The Energy In Transition: Energy is a physical quantity and it can move from one system to another system, from one place to another place. How does energy crosses the boundary of a system? From where energy knows the direction of travel? Those are some questions which scientists want to deliver an elusive but convincing answer.

                                     So, in thermodynamics, energy will flow either as radiation (heat) or as Workdone otherwise. Hence thermodynamic work has a large domain in which mechanical work is a sub domain.


TOTAL ENERGY CONTENT OF AN AMOUNT OF GAS ENCLOSED IN A VESSEL

                                     Suppose we have an enclosed vessel, where we have kept certain amount of gas. The molecules of the gas possess energy due to the molecular vibrations of the gas molecules due to Brownian Motion. Energy, thus stored as kinetic energy of the gas molecules directly depends upon the temperature of the body. For a perfect gas the kinetic energy of the molecules, energy of a molecule directly depends upon its temperature. This energy is termed as Internal Energy. It is denoted by U. Where as internal energy per unit mass is named as Specific Internal Energy and denoted by (u) Or we can write
U=m.u where m= mass of the working substance. And if Cv is the specific heat at constant volume. Now we can write, dU = m.Cv.(dt), where as the dt is the elementary change in the temperature. But, in addition to this internal energy, there is one more type of energy. To gather all the molecules of the gas from infinity distance to enclose them at the pressure P and volume V needs workdone on the molecules, this workdone is stored in the molecules as Flow Energy and is equal to PV, hence total energy possessed by the gas molecules will be the sum of internal energy and flow work, and it is called as Enthalpy denoted by H.

H = U + PV
or
h = u + Pv (in terms of specific properties)


INEXACT DIFFERENTIALS AND EXACT  DIFFERENTIALS:

                                     In thermodynamics, an inexact differential or imperfect differential is any quantity, particularly heat Q and work W, that are not state functions (a property of a system that depends only on the current state of the system, not on the way in which the system acquired that state), in that their values depend on how the process is performed. The symbol ,₫ or δ (in the modern sense), which originated from the work of German mathematician Carl Gottfried Neumann in his 1875 Vorlesungen über die mechanische Theorie der Wärme, indicates that Q and W are path dependent. In terms of infinitesimal quantities, the first law of thermodynamics is thus expressed as:

δQ = dU + δW

where δQ and δW are inexact (path-dependent), and dU is exact (path-independent).


For an exact differential df, An inexact differential is one whose integral is path dependent. This may be expressed mathematically for a function of two variables as






                                     A differential dQ that is not exact is said to be integrable when there is a function 1/τ such that the new differential dQ/τ is exact. The function 1/τ is called the integrating factor, τ being the integrating denominator.

                                     As an example, the use of the inexact differential in thermodynamics is a way to mathematically quantify functions that are not state functions and are thus path dependent. In thermodynamic calculations, the use of the symbol ΔQ for heat is a mistake, since heat is not a state function having initial and final values. It would, however, be correct to use lower case δQ in the inexact differential expression for heat. The offending Δ belongs further down in the Thermodynamics section in the equation , which should be (Baierlein, p. 10, equation 1.11, though he denotes internal energy by E in place of U).[3] Continuing with the same instance of ΔQ, for example, removing the Δ, the equation
is true for constant pressure.


LAWS OF THERMODYNAMICS

                                    Temperature; a vital characteristics of stored energy in molecules. In a sense we can say the effect of energy stored in a molecule is the temperature of the molecule. In classical thermodynamics, temperature of a gas is nothing but the average kinetic energy of a molecule. In fact thermodynamics is the subject which deals with Energy, Equilibrium, Entropy often described as the study of  "EEE". "Molecular Motion" is the theme of thermodynamics.

                                    Thermodynamics is nothing but the energy mechanics ie the movement of energy in the space and time. It is quite evident from the name of the subject. "Thermos" is heat related to temperature and "dynamics" is the motion of it. The manifestation of energy trapped within a body is nothing but the temperature.

                                     I was an observer of nature. The smallest of smalls are the components of the nature too. I still remember the day I first time saw a thermometer, I was badly attacked by viral fever. I remember my aunt told me to clasp a thin pipe of glass, with a glittering substance inside sandwiched by inner side of my left arm and the arm pit. When I asked about the object I was told that it was an instrument, that the instrument measures the magnitude of hotness or coldness and named as "thermometer".

                                    The question that immediately popped up in my mind is that how does it measure the hotness of any object. I asked my teachers at the school, but nothing new had come out, but one thing was common in their reply to my queries and it was that whenever we place an object inside a fire, the object becomes hotter and hotter as temperature would rise and we can measure it as it would produce a rise in mercury columns.

                                    I came to know the exact answer to my queries when I read thermodynamics in the 11th Standard. when I read about kinetic theory of gases, where temperature was defined by the average magnitude of the kinetic energy of the molecules due to their non stop & compulsory motions which was analyzed by Albert Einstein and the phenomenon is called "Brownian Motion".

                                   When we touch a hot body, we feel the temperature as the molecules would transfer kinetic energy to my finger and the energy was converted into heat energy. So "Temperature" of a body is a macroscopic property of the body as a manifestation of energy contained in the whole body and which arises due to continuous bombardment of molecules with a high kinetic energy and transfer a portion of that energy to the body which is converted to heat.

                                   But it must not be the complete explanation as in solids there would not be any 'Brownian Motion' unlike the molecules of a fluid, but despite this solid still have a temperature. What is the reason of this temperature? Is it still molecular kinetic energy due to which solid posses temperature?

                                   In solid molecules are fixed at lattice points, a molecule needs a large amount of energy to make itself free from the shackles of lattice. But molecules still posses energy as it can still vibrate about its mean point ie. lattice point. This vibrational energy is responsible for solid's temperature.


Friday, 29 May 2009

MULTIPLE CHOICE QUESTIONS: ENGINEERING MECHANICS

Choose the correct answer:

Q.1) In a simply supported beam of length L, a UDL of w kN/m acts on the entire span of the beam. The maximum bending moment will be
a. (w.L2)/8 b. (w.L3)/8 c. (w.L2)/4 d. (w.L3)/4

Q.2) If two forces are acting on a particle and the particle is in a stable equilibrium, then the forces are,
a. equal to each other
b. equal but opposite in direction
c. they are unequal but the direction is same.
d. none of the above.

Q.3) The example of Statically indeterminate structures are,
a. continuous beam,
b. cantilever beam,
c. over-hanging beam,
d. both cantilever and fixed beam.

Q.4) A redundant truss is defined by the truss satisfying the equation,
a. m = 2j - 3,
b. m < 2j + 3,
c. m > 2j - 3,
d. m > 2j + 3

Q.5) The property of a material to withstand a sudden impact or shock is called,
a. hardness b. ductility,
c. toughness, d. elasticity
of the material.

Q.6) The stress genarated by a dynamic loading is approximately _____ times of the stress developed by the gradually applying the same load.

Q.7) The ratio between the volumetric stress to the volumetric strain is called as
a. young's modulus
b. modulus of elasticity
c. rigidity modulus,
d. bulk modulus.

Q.8) In a Cantilever beam, the maximum bending moment is induced at
a. at the free end
b. at the fixed end
c. at the mid span of the beam
d. none of the above.

Q.9) The forces which meet at a point are called
a. collinear forces
b. concurrent forces
c. coplanar forces
d. parallel forces.

Q.10) The coefficients of friction depends upon
a. nature of the surface
b. shape of the surface
c. area of the contact surface
d. weight of the body.

Q.11) The variation of shear force due to a triangular load on simply supported beam is
a. uniform b. linear
c. parabolic d. cubic.

Q.12) A body is on the point of sliding down an inclined plane under its own weight. If the inclination of the plane is 30 degree, then the coefficient of friction between the planes will be
a. (1/3)½ b. 3½ c. 1 d. 0

Wednesday, 14 January 2009

CARBURETTOR AND THE PROCESS OF CARBURETION

 

CARBURETOR                                                                                  Subhankar Karmakar

DEFINITION: A carburetor is a device that mixes air and fuel in the correct proportion for combustion in an internal combustion engine. The process of mixing air and fuel in a carburetor is known as carburetion.


STRUCTURE: The carburetor has a narrow opening called the throttle, which controls the amount of air that enters the engine. When the throttle is opened, air is drawn into the carburetor and mixed with fuel. The amount of fuel that is mixed with the air is controlled by a valve called the fuel valve, which regulates the flow of fuel into the carburetor.

 

Once the air and fuel are mixed, the resulting mixture is drawn into the engine through the intake manifold. The fuel and air mixture is then ignited by a spark plug, which causes the fuel to burn and produce energy. This energy is used to power the engine and propel the vehicle.

 

The carburetor must be adjusted to ensure that the fuel and air mixture is correct for the specific engine and driving conditions. If the mixture is too lean (too much air and not enough fuel), the engine will run poorly and may even overheat. If the mixture is too rich (too much fuel and not enough air), the engine may run rough and produce excessive emissions.

 

Carburetors were commonly used in older cars, but they have been largely replaced by fuel injection systems in modern vehicles. However, they are still used in some small engines, such as those found in lawnmowers and chainsaws.

 

CARBURETOR IN PETROL ENGINE:

 

A carburetor is a device that mixes air and fuel in the correct ratio before it enters the engine's combustion chamber. It was commonly used in older petrol (gasoline) engines before the advent of electronic fuel injection systems.

 

The basic principle of operation of a carburetor is that it uses a venturi, a narrow section of the carburetor through which air is forced to flow at high speed. As the air moves through the venturi, it creates a vacuum that draws fuel into the airflow, which mixes with the air and forms a combustible mixture.

 

The carburetor consists of several components, including a throttle valve, a choke, an idle speed adjustment screw, and a fuel bowl. The throttle valve controls the amount of air entering the engine, while the choke is used to enrich the air-fuel mixture when starting the engine. The idle speed adjustment screw regulates the engine's idle speed, while the fuel bowl stores the fuel that is drawn into the carburetor.

 

While modern petrol engines typically use electronic fuel injection systems, carburetors are still used in some older engines, as well as in small engines such as those used in lawnmowers, chainsaws, and other small equipment.

 

CARBURETOR IN DIESEL ENGINE:

 

A carburetor is a device used in gasoline engines to mix air and fuel in the correct proportions before it enters the engine cylinders for combustion.

 

However, diesel engines do not use carburetors. Instead, they use a fuel injection system, which injects fuel directly into the combustion chamber at the appropriate time, under high pressure.

 

In a diesel engine, air is compressed in the cylinder, causing it to heat up. When the air is hot enough, fuel is injected into the combustion chamber, where it ignites spontaneously due to the high temperature and pressure, without the need for a spark plug.

 

The fuel injection system in a diesel engine is more complex than a carburetor and requires precise control over the amount and timing of fuel injection to optimize combustion efficiency and reduce emissions.

COMPONENTS OF A CARBURETOR:

Carburetor in Petrol (Gasoline) Engine:

A carburetor is a crucial component in older petrol engines, responsible for mixing air and fuel in the correct ratio before it enters the engine's combustion chamber. Here's a more detailed breakdown of its components and operation:

  1. Venturi Principle: The core principle behind a carburetor's function is the Venturi effect. A venturi is a narrow section within the carburetor where air is forced to flow at high speeds. As air passes through the venturi, it accelerates, creating a region of low pressure. This low-pressure area effectively "sucks" fuel from a reservoir into the air stream.
  2. Throttle Valve: The throttle valve, also known as the butterfly valve, controls the amount of air entering the engine. When you press the accelerator pedal, it opens the throttle valve wider, allowing more air to pass through, and vice versa.
  3. Choke: The choke is a mechanism used to enrich the air-fuel mixture when starting a cold engine. By restricting the airflow, it increases the fuel-to-air ratio, making it easier for the engine to start in cold conditions.
  4. Idle Speed Adjustment Screw: This screw allows adjustment of the engine's idle speed. By controlling the amount of air allowed to bypass the closed throttle valve, it regulates the engine's speed when it's not under load.
  5. Fuel Bowl: The fuel bowl is a reservoir that stores fuel. Fuel is drawn from the bowl into the venturi as needed to maintain the correct air-fuel mixture.

Carburetor in Diesel Engine:

Diesel engines operate differently from petrol engines, and they do not use carburetors. Instead, they employ a fuel injection system, which works as follows:

  1. Compression Ignition: Diesel engines rely on high compression ratios to generate the heat needed for ignition. As air is compressed within the cylinder, its temperature increases significantly. When the piston reaches the top of its compression stroke, fuel is directly injected into the hot, highly compressed air.
  2. Fuel Injection System: Diesel fuel injection systems are highly precise and operate under high pressure. They consist of injectors that spray a fine mist of diesel fuel directly into the combustion chamber at the precise moment required for ignition. The injection timing and quantity are controlled electronically or mechanically for optimal efficiency and emissions control.
  3. No Spark Plugs: Unlike petrol engines, diesel engines do not require spark plugs because the high temperature and pressure in the cylinder are sufficient to ignite the fuel without the need for an external spark.

While carburetors were widely used in older petrol engines, diesel engines operate on a different principle altogether, using fuel injection systems to introduce fuel directly into the combustion chamber. Modern petrol engines have also largely transitioned to electronic fuel injection systems due to their efficiency and emissions control advantages. Carburetors are still found in some older engines and small equipment, but they are becoming increasingly rare in automotive applications.