Thursday, 1 December 2011

SOLUTION OF EME-102; CENTROID





HOW TO FIND THE CENTROID OF A COMPOSITE AREA

(a composite area consists of several straight or curved lines.)

(i) Draw the figure in a coordinate system. Draw the dimensions too. Every dimensions will be measured with respect to origin of the coordinate system


(ii) Divide the composite area into several parts of basic geometric areas. Lebel them as part-1, part-2, part-3, .......part-n. Let the corresponding areas are A1, A2, A3, .... An. Let the centroids are G1(X1,Y1), G2(X2,Y2), G3(X3,Y3), ...... Gn(Xn,Yn).

(iii) Let the centroid of the composite area be G(Xg,Yg). Hence,
Xg = (A1X1 + A2X2 +A3X3)/(A1 + A2 + A3)

Yg = (A1Y1 + A2Y2 +A3Y3)/(A1 + A2 + A3)




 
(a) Suppose we have certain area of magnitude (A) in a coordinate system. The centroid of the area will be at its mid-point. A centroid is denoted by G.

                       In the figure we have a complex geometrical area composed of three basic geometrical areas. A rectangle, a semi circle and a isosceles triangle. Let us denote the centroids as G1, G2, G3 for the given areas in the figure.

We shall have to find the Centroid of the entire area composed of  A1, A2, A3.

At first, the composite line is divided into three parts.


Part -1 : The semi-circle : Let the centroid of the area A1 be G1(X1,Y1)

Area, A1 = (π/2)x(25)² mm² = 981.74 mm²                  
          X1 = { 25 -  (4x25)/(3xπ)} mm = 14.39 mm
          Y1 = 25 mm


Part -2 : The Rectangle : Let the centroid of the A2 be G2(X2,Y2)


Area, A2 = 100 x 50  mm² = 5000 mm²             
          X2 = 25 + (100/2) = 75 mm
          Y2 = 25 mm
Part -3 : The Triangle : Let the centroid of the area Area, A3 be G3(X3,Y3)


Area, A3 = (1/2) x 50 x 50 mm² = 1250 mm²             
          X3 = 25 + 50 + 25 = 100 mm
          Y3 = 50 + (50/3) =  66.67 mm






If the centroid of the composite line be G  (Xg,Yg)
Xg = (∑AiXi)/(∑Ai


    = (A1X1 + A2X2 +A3X3)/(A1 + A2 + A3)
    = (981.74 x 14.39 + 5000 x 75 + 1250 x 100)/( 981.74 + 5000 + 1250)
    = 71.09
     
Yg = (∑AiYi)/(∑Ai


    = (A1Y1 + A2Y2 +A3Y3)/(A1 + A2 + A3)
    = (981.74 x 25 + 5000 x 25 + 1250 x 66.67)/ ( 981.74 + 5000 + 1250)
    = 32.20

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